Shear Face
Find the horizontal distance traveled by the sheared face of the sole.?
A child slides across a floor in a pair of rubber-soled shoes. The friction force acting on each foot is 22 N, the footprint area of each foot is 15 cm^2, and the thickness of the soles is 5.0 mm. Find the horizontal distance traveled by the sheared face of the sole. The shear modulus of the rubber is 3.0 x 10^6 Pa.
I’ve been working on this problem way longer than it should take and feel like I am missing something. Although, there is a problem like this in the text book, there is not examples of how to work it out.
I know:
(F/A)=S(delta x / h)
I am solving for delta x, since that represents the distance traveled by the top surface of the rubber soles. So: delta x= (Fh/A)/S
I’ve converted everything into meters, since that is what web assign is asking the answer to be reported in.
So… what am I missing?
As you compute,
dx = Fh/(AS) = 22*.005/(.0015*3E6) = 24.4E-6 m = .0244 mm
This should be the correct answer. Did you get all your unit conversions right?
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